(2/x-2)+x=x^2

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Solution for (2/x-2)+x=x^2 equation: 



(2/x-2)+x=x^2

We move all terms to the left:

(2/x-2)+x-(x^2)=0



Domain of the equation: x-2)!=0

x∈R



determiningTheFunctionDomain
-x^2+(2/x-2)+x=0

We add all the numbers together, and all the variables

-1x^2+x+(2/x-2)=0

We get rid of parentheses

-1x^2+x+2/x-2=0

We multiply all the terms by the denominator


-1x^2*x+x*x-2*x+2=0

We add all the numbers together, and all the variables

-1x^2*x-2x+x*x+2=0

Wy multiply elements

-1x^3+x^2-2x+2=0

We do not support expression: x^3

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